Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.2 - Problems - Circuits, Currents, and Voltages - Page 35: P1.14

Answer

$3.125 \times 10^{19}$ electrons cross each second

Work Step by Step

Total charge crossing in one second = current $\times$ 1 = 5 C No. of electrons crossing per second = $\frac{total charge crossing per second}{charge of each electron}$ = $\frac{5}{1.6 \times 10^{-19}}$ = $3.125 \times 10^{19}$
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