Answer
$433 per kWhr
Work Step by Step
$9V\times50mA\times10hr = 0.0045kWhr$
$\$1.95\div0.0045kWhr=\$433.33\ per\ kWhr$
Electrical Engineering: Principles & Applications (6th Edition)
by Hambley, Allan R.
Published by
Prentice Hall
ISBN 10:
0133116646
ISBN 13:
978-0-13311-664-9
Chapter 1 - 1.3 - Problems - Power and Enery - Page 36: P1.30
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