Fundamentals of Electrical Engineering

Published by McGraw-Hill Education
ISBN 10: 0073380377
ISBN 13: 978-0-07338-037-7

Chapter 4 - AC Network Analysis - Part 1 Circuits - Homework Problems - Page 167: 4.1

Answer

$V = -337*sin(377*t + \pi/6)$ (Volts)

Work Step by Step

Start with the equation $V = L * \frac{di}{dt}$ $L = 0.5H$ Take the derivative of the given current through the inductor to find the voltage $ V = 0.5*(-2*377*sin(377*t +\pi/6))$ $V = -377*sin(377*t+\pi/6)$ Volts
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