Fundamentals of Electrical Engineering

Published by McGraw-Hill Education
ISBN 10: 0073380377
ISBN 13: 978-0-07338-037-7

Chapter 4 - AC Network Analysis - Part 1 Circuits - Homework Problems - Page 173: 4.56

Answer

$I_1 = 8.944*e^{-0.856*j} $A

Work Step by Step

This problem is approached by using a current divider using impedance instead of regular resistance. Calculate parallel impedance $Z_{||} = \frac{2*(-4j)}{2-4j} \Omega$ $Z_{||} = \frac{(-4j)}{1-2j} \Omega$ Now use the current divider formula $I_1 = 10*e^{-j*\pi /8} *\frac{Z_{||}}{Z_1}$ $I_1 = 10*e^{-j*\pi /8} *\frac{-2j}{1-2j}$ Use a calculator with complex capabilities to solve for the final current i1 $I_1 = 8.944*e^{-0.856*j} $ A
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