Answer
$ß=120$
$F_x=40.0N$
$F_y=40.0N$
$F_z=56.6N$
Work Step by Step
$Using $
$cos^2α+cos^2ß+cos^2δ=1$
$ß=cos^{-1}\sqrt {1-cos^2α-cos^2δ}$
$ß=cos^{-1}\sqrt {1-cos^260-cos^245}$
$ß=120.0$
$F_x=Fcosα=80cos60=40N$
$F_y=Fcosß=80cos120=40N$
$F_z=Fcosδ=80cos45=56.6N$
