Answer
$\begin{aligned} & V_c=-133 \mathrm{lb} \\ & M_C=133 \mathrm{lb} \cdot \mathrm{in} .\end{aligned}$
Work Step by Step
$$
\begin{array}{cl}
+\Sigma M_A=0 ; & -20(10)+R_B(1.5)=0 \\
& R_B=133.3 \mathrm{lb}
\end{array}
$$
Segment $B C$ :
$$
\begin{array}{ll}
+\nearrow \Sigma F_y=0 ; & V_C+133.3=0 \\
& V_C=-133 \mathrm{lb} \\
↺+\Sigma M_C=0 ; & -M_C+133.3(1)=0 \\
& M_C=133 \mathrm{lb} \cdot \mathrm{in} .
\end{array}
$$
