Answer
$\begin{aligned} & V_C=0 \\ & M_C=8.10 \mathrm{kip} \cdot \mathrm{ft}\end{aligned}$
Work Step by Step
Support Reactions.
$
\begin{array}{ccc}
\zeta+\Sigma M_B=0 ; & 500(12)(6)+900-900-A_y(12)=0 & \\A_y=3000 \mathrm{lb} \\
\rightarrow \Sigma F_x=0 ; & A_x=0 &
\end{array}
$
Internal Loadings.
$
\begin{array}{r}
+\uparrow \Sigma F_y=0 ; \quad 3000-500(6)-V_C=0 \quad V_C=0 \\
\zeta+\Sigma M_C=0 ; \quad M_C+500(6)(3)+900-3000(6)=0 \\
M_C=8100 \mathrm{lb} \cdot \mathrm{ft}=8.10 \mathrm{kip} \cdot \mathrm{ft}
\end{array}
$
