Shigley's Mechanical Engineering Design 10th Edition

Published by McGraw-Hill Education
ISBN 10: 0073398209
ISBN 13: 978-0-07339-820-4

Chapter 1 - Problems - Page 37: 1-12

Answer

d = 1.006 in d = 1.25 in n = 4.79

Work Step by Step

$\sigma = \frac{S}{n_d}=\frac{32(1000)}{\pi d^3}=\frac{25(10^3)}{2.5}\rightarrow d = 1.006$ in Table A-17: $d=1.25$ in Factor of safety: $n = \frac{S}{\sigma}=\frac{25(10^3}{\frac{32(1000)}{\pi (1.25)^3}}=4.79$
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