Chapter 1 - Problems: Developing Engineering Skills - Page 31: 1.24

In this problem, According to the equation, P= A+(B/V) we know that same dimensions are additive, and they give the same dimension as each of the added quantity, so clearly, A has the dimensions of P i.e lbf/$ft^{2}$, also (B/V) also has dimensions of P and V or volume has the dimensions of $ft^{3}$ so B=PV = (lbf/$ft^{2}$)($ft^{3}$) = ft.lbf

In this problem, According to the equation, P= A+(B/V) we know that same dimensions are additive, and they give the same dimension as each of the added quantity, so clearly, A has the dimensions of P i.e lbf/$ft^{2}$, also (B/V) also has dimensions of P and V or volume has the dimensions of $ft^{3}$ so B=PV = (lbf/$ft^{2}$)($ft^{3}$) = ft.lbf