Answer
We know that ,
(COP)beta = $Q_{in}$ /$W_{cycle}$
here we are given beta = 2.93 and $Q_{in}$ = 5000 Btu/h
So, $W_{cycle}$ = $Q_{in}$/beta
1 W = 3.413 Btu/h
$W_{cycle}$ = ( 5000 Btu/h) ( 8 h/day ) (125 days/season)|1 kW/ 3413 Btu/h|
= 500 kW.h/season
Costing ,
$ = ( 500 kW.h/season)( $0.10/kW.h)
= $50/season .
Work Step by Step
We know that ,
(COP)beta = $Q_{in}$ /$W_{cycle}$
here we are given beta = 2.93 and $Q_{in}$ = 5000 Btu/h
So, $W_{cycle}$ = $Q_{in}$/beta
1 W = 3.413 Btu/h
$W_{cycle}$ = ( 5000 Btu/h) ( 8 h/day ) (125 days/season)|1 kW/ 3413 Btu/h|
= 500 kW.h/season
Costing ,
$ = ( 500 kW.h/season)( $0.10/kW.h)
= $50/season .
