Chapter 3 - The Structure of Crystalline Solids - Questions and Problems - Page 100: 3.39a

$(1,0,1)$, $(-1,0,-1)$ $(0,-1,-1)$ $(0,-1,1)$ $(0,1,-1)$ $(1,0,-1)$ $(-1,0,1)$

$x_{1}=y_{1}=z_{1}=0$ . Tetragonal unit cell $a = b \ne c$ Now the point $x_{2}=0a=0$ $y_{2}=b=a$ and $z_{2}=c$ vector length =$\sqrt{x^2+y^2+z^2}=\sqrt{a^2+c^2}$ Then the point will be $(1,0,1)$, $(-1,0,-1)$ $(0,-1,-1)$ $(0,-1,1)$ $(0,1,-1)$ $(1,0,-1)$ $(-1,0,1)$