Answer
d. 10°C
Work Step by Step
50 L = 50,000 g
500 kcal = 500,000 cal
1 cal/g = specific heat of water
500,000 cal = 50,000 g x 1 cal/g x $\Delta$T
500,000/50,000 cal/g = 10$^{\circ}$ C
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