Campbell Biology (11th Edition)

Published by Pearson
ISBN 10: 0-13409-341-0
ISBN 13: 978-0-13409-341-3

Chapter 3 - Test Your Understanding - Level 2 - Application/Analysis - Page 55: 5

Answer

d. 10°C

Work Step by Step

50 L = 50,000 g 500 kcal = 500,000 cal 1 cal/g = specific heat of water 500,000 cal = 50,000 g x 1 cal/g x $\Delta$T 500,000/50,000 cal/g = 10$^{\circ}$ C
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