Lehninger Principles of Biochemistry 6th Edition

Published by W.H. Freeman
ISBN 10: 1-42923-414-8
ISBN 13: 978-1-42923-414-6

Chapter 2 - Water - Problems - Page 71: 7

Answer

1.79 moles

Work Step by Step

For every acetylcholine, a hydrogen ion is released in the reaction which means [H] produced during the reaction = Acetylcholine concentration. [H] produced during reaction = [H] at the end- [H] at start of reaction [H] = $10^{-pH}$ [H] at start of reaction = $10^{-7.65}$ = $0.224 \times 10^{-7}$M [H] at the end of reaction = $10^{-6.87}$ = $1.35 \times 10^{-7}$M [H] produced during reaction = $(1.35 -0.224) \times10^{-7}$M =1.13M This is equal to acetylcholine concentration $1.13 \times10^{-7}$ moles in 1 liter In 15 mL or 0.0015 L, the number of moles = $1.13 \times10^{-7} \times 0.0015 L $ = $1.7 \times10^{-9}$ moles
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.