Chemistry (12th Edition)

by Wilbraham

Published by Prentice Hall

ISBN 10: 0132525763

ISBN 13: 978-0-13252-576-3

Chapter 12 - Stoichiometry - 12 Assessment - Page 413: 68

Answer

0.784 L NO

Work Step by Step

(1.4L O2 * 1 mol O2 * 4 mol NO * 22.4L NO)/(32g O2 * 5 mol O2 * 1 mol NO) Liters = 0.784 L NO

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