Answer
$x=2.2\times10^{-4}mol/L$
Work Step by Step
1. Write Balanced Equilibrium Equation
$CaF_{2}⇄Ca^{2+}+2F^{-}$
2. Write Ksp equation
$K_{sp}=(x)(2x)^2$
$4.0\times10^{-11}=x(2x)^2$
$x=2.2\times10^{-4}mol/L$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 16 - Acid-Base Equilibria and Solubility Equilibria - Questions & Problems - Page 767: 16.58
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