Answer
$1\times10^8$ helium atoms
Work Step by Step
diameter of helium atom: $1\times10^2pm$ = $1\times10^{-10}m$
distance = 1 cm = $1\times10^{-2}m$
number of helium atoms = $\frac{1\times10^{-2}}{1\times10^{-10}}$
= $1\times10^8$ helium atoms
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 2 - Atoms, Molecules, and Ions - Questions & Problems - Page 68: 2.7
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