Answer
Please see the work below.
Work Step by Step
We know that
$0.334g\space C_2H_5\times \frac{1mol\space C_2H_6}{30.068g\space C_2H_6}\times \frac{6.022\times 10^{23}C_2H_6molecules }{1mol\space C_2H_6}=6.69\times 10^{23}C_2H_6molecules$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 107: 3.26
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
