Answer
3.6 mol $CO_{2}$
Work Step by Step
$2CO(g)+0_{2}(g)$ -> $2CO_{2}(g)$
mol of $CO_{2}$=
$\frac{(3.6 mol CO)\times(2 mol CO_{2})}{(2 mol CO)}$
= 3.6 mol $CO_{2}$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 109: 3.65
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