Answer
= 0.3005 mol of $H_{2}O$
Work Step by Step
$CuSO_{4}5H_{2}O$ -> $CuSO_{4}+5H_{2}O$
mol of$H_{2}O$= $\frac{(15.01gCuSO_{4}5H_{2}O)\times(1molCuSO_{4}5H_{2}O)\times(5molH_{2}O)}{(249.72gCuSO_{4}5H_{2}O)\times(1molCuSO_{4}5H_{2}O}$
= 0.3005 mol
