Answer
(a) $0.212 mole$
(b) $ 0.424mole$
Work Step by Step
Equation for the formation of CO,
$ C + 1/2O_{2(g)} → CO_{(g)}$
From the equation we have,
1 mole of Carbon completely reacts with 0.5 mole of $O_{2(g)}$ to form 1 mole CO.
Therefore number of moles $O_{2(g)}$ required to combine with 0.212 mole of C =
$ (0.212 \times 0.5) = 0.103 mole$
Hence number of moles $O_{2(g)}$ required to combine with 0.212 mole of C =
$ (0.212 \times 0.5) = 0.106 mole$
1 mole $O_{2}$ contains 2 mole of $O$ atoms.
Therefore, the number of moles $O$ required to combine with 0.212 mole of C = $ (0.103 \times 2 ) = 0.212 mole$
Equation for the formation of $CO_{2(g)}$,
$ C + O_{2(g)} → CO_{2(g)}$
From the equation we have,
1 mole of Carbon completely reacts with 1 mole of $O_{2(g)}$ to form 1 mole $CO_{2(g)}$.
1 mole $O_{2}$ contains 2 mole of $O$ atoms.
Therefore number of moles $O$ required to combine with 0.212 mole of C =$ 2 \times 0.212 = 0.424mole$
