Answer
Please see the work below.
Work Step by Step
We know that:
$M_1V_1=M_2V_2$
Where $M_1$ is the concentration of the original solution and $V_1$ is the volume of the original solution. $M_2$ and $V_2$ are the concentration and final volume of the diluted solution, respectively.
We plug in the known values into the above equation to obtain:
$0.200\times 0.0600L=4.00\times V_2$
$V_1=0.00300L=3.0mL$
