Answer
Please see the work below.
Work Step by Step
We know that:
$P_fV_f=P_iV_i$
This can be rearranged as:
$V_f=\frac{P_iV_i}{P_f}$
We plug in the known values to obtain:
$V_f=\frac{1.2(3.8)}{6.6}=0.69L$
(b) We know that $P_f=\frac{P_iV_i}{V_f}$
We plug in the known values to obtain:
$P_f=\frac{1.2(3.8)}{0.075}=60.8atm$
