Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 1 - Questions and Problems - Page 32: 1.48

Answer

(a) $ 1.4598 \times 10^2$ (b) $ 3.2 \times 10^2$ (c) $ 6.2 \times 10^{-3}$ (d) $9.9 \times 10^{10}$

Work Step by Step

(a) $ 145.75 + 0.23 = 145.98 = 1.4598 \times 10^2$ (b) $79500/(2.5 \times 10^2) = \frac{79500}{2.5} \times 10^{-2} = 32000 \times 10^{-2} = 3.2 \times 10^2$ (c) $70 \times 10^{-4} - 8.0 \times 10^{-4} = 62 \times 10^{-4} = 6.2 \times 10^{-3}$ (d) $1.0 \times 9.9 \times 10^{10} = 9.9 \times 10^{10}$
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