Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Section 10.6 - The Kinetic Molecular Theory of Gases - Checkpoint - Page 460: 10.6.1

Answer

$\therefore$ $CH_{3}Br$ will be the unknown gas

Work Step by Step

$Rate\propto \frac{1}{\sqrt M}$ $Rate_{CH_4} = 2.4\times Rate_{unknown}$ $\frac{Rate_{CH_4}}{Rate_{unknown}} = \frac{\sqrt M_{unknown}}{\sqrt M_{CH_4}}$ $\sqrt M_{unknown} = 2.4\times 4 $ $\sqrt M_{unknown} = 9.6 $ $M_{unknown} = 92.16 g$ $\therefore$ $CH_{3}Br$ will be the unknown gas
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