Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 2 - Section 2.1 - The Atomic Theory - Checkpoint - Page 43: 2.1.2

Answer

option b is correct

Work Step by Step

so here we have to solve step by step for every pair of compounds to get the ratio 4:1 For a) $\frac{g\space yellow : 1.00 g\space blue (right}{g\space yellow: 1.00 g \space blue (left)}$ = $\frac{3.00g\space yellow : 1.00 g\space blue (right}{1.00g\space yellow: 1.00 g \space blue (left)}$= 3:1 For b) $\frac{g\space yellow : 1.00 g\space blue (right}{g\space yellow: 1.00 g \space blue (left)}$ = $\frac{2.00g\space yellow : 1.00 g\space blue (right}{1.00g\space yellow: 2.00 g \space blue (left)}$=4:1 which is the correct answer, so option b) is right option c , d and e and be solved similarly.
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