Answer
b) is the correct answer.
$$2.83 \times 10^{23} \space molecules \space SO_2 $$
Work Step by Step
- Calculate the molar mass for $ SO_2 $:
$ SO_2 $ : ( 16.00 $\times$ 2 )+ ( 32.07 $\times$ 1 )= 64.07 g/mol
- Using the molar mass as a conversion factor, find the amount in moles:
$$ 30.1 \space g \times \frac{1 \space mole}{ 64.07 \space g} = 0.470 \space mole$$
$$ 0.470 \space mole \space SO_2 \times \frac{6.022 \times 10^{23} \space molecules \ SO_2 }{1 \space mole \space SO_2 } = 2.83 \times 10^{23} \space molecules \space SO_2 $$
