Answer
$4.64 \cdot 10^-20$ g Fe
Work Step by Step
(500 atoms)$(\dfrac{1 mol}{6.022 \cdot 10^{23}molecules})(\dfrac{55.85g}{1mol})$ = $4.64 \cdot 10^-20$ g Fe
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 3 - Stoichiometry - Exercises - Page 128: 45
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