Answer
$^{214}_{82}Pb\ -->\ ^{214}_{83}Bi + ^{0}_{-1}e$
Work Step by Step
a Pb-214 nuclide emits a beta particle causing one of its neutrons to become a proton making it a Bi-214 nuclide.
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 945: 31c
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
