Chemistry: A Molecular Approach (3rd Edition)

by Tro, Nivaldo J.

Published by Prentice Hall

ISBN 10: 0321809246

ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic - Page 82: 83d

Answer

$$0.0304 mol Li$$

Work Step by Step

1. Use the molar mass of this element as a conversion factor in order to convert grams into moles. 2. $0.211 g Li\times\frac{1 mol Li}{6.941 g Li}=0.0304 mol Li$

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