Answer
$HNO_3 - NO{_3}^-$ and $NH_3-NH{_4}^+$ are the conjugate acid-base pairs.
Work Step by Step
1. Identify the acid and the base in the reactants side:
- $HNO_3$ is donating a proton $(H^+)$ to $NH_3$. Therefore, $HNO_3$ is the acid and $NH_3$ is the base.
2. Determine the conjugate base.
- The acid is: $HNO_3$.
- When it loses a proton, it becomes $NO{_3}^-$. Thus, $NO{_3}^-$ is the conjugate base.
- The first conjugate acid-base pair is $HNO_3 - NO{_3}^-$.
3. Determine the conjugate base.
- The base is: $NH_3$.
- When it receives a proton, it becomes $NH{_4}^+$. Thus, $NH{_4}^+$ is the conjugate acid.
- The second conjugate acid-base pair is $NH_3-NH{_4}^+$
