Chapter 18 - Section 18.8 - Degradation of Amino Acids - Additional Questions and Problems - Page 667: 18.76

$42.46\space mole \space of ATP$

We know that from hydrolysis reaction of $ATP$ that it gives $7.3KCal$ energy that is $7.3Kcal=1mol ATP$ $\implies 1Kcal=\frac{1mol \space ATP}{7.3Kcal}$ $\implies 310Kcal=\frac{310Kcal}{7.3Kcal}mol \space ATP=42.46\space mole \space of ATP$