Answer
1360 J, 330 cal
Work Step by Step
$\Delta T = 12.5^{o}C - 25.7^{o}C = -13^{o}C$
Heat = mass x $\Delta T$ x SH
Heat (J)= 25g x $-13^{o}C$ x 4.184 J / g $^{o}C$
= 1360 J
Heat (cal)= 25g x $-13^{o}C$ x 1 cal / g $^{o}C$
= 325 cal
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)
by Timberlake, Karen C.
Published by
Prentice Hall
ISBN 10:
0321908449
ISBN 13:
978-0-32190-844-5
Chapter 3 - Section 3.6 - Specific Heat - Questions and Problems - Page 75: 3.37a
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