Chapter 18 Principles of Chemical Reactivity: Entropy and Free Energy - 18-7 Calculating and Using Free Energy - Review & Check for Section 18-7 - Page 708: 1

(c) $-2155\text{ kJ/mol-rxn}$

$\Delta_{r}G^{\circ}=\Delta _{r}H^{\circ}-T\Delta_{r}S^{\circ}$ $=(-2219\text{ kJ/mol-rxn})-(25+273)\text{K}(-216\text{ J/K mol-rxn})$ $=(-2219\text{ kJ/mol-rxn})+(64368\text{ J/mol-rxn})$ $=(-2219\text{ kJ/mol-rxn})+(64.368\text{ kJ/mol-rxn})$ $=-2155\text{ kJ/mol-rxn}$