Answer
$104.03\ g/mol$
Work Step by Step
Number of moles of the base:
$0.509\ M\times 36.04\ mL=18.34\ mmol$
From stoichiometry:
$9.17\ mmol$ of acid.
Molar mass:
$954\ mg\div 9.17\ mmol=104.03\ g/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179f: 73
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