Answer
See explanation
Work Step by Step
$Al_2O_3$ being amphoteric means it can act as both an acid and a base. It can react with both acids and bases to form salts.
$Al_2O_3+6H^+\rightarrow 2Al^{3+}+3H_2O$
$Al_2O_3+2OH^-+3H_2O\rightarrow 2Al(OH)^{-}_4$
