Answer
a) 2,2-dibromo-3-methylpentane
b) 3-iodo-4-ethyl-2-methylhexane
c) 4-fluoro-2-methylnonane
Work Step by Step
a) No. of C in straight chain = 5. hence, root name is 'pent' and ending name is 'ane' for alkane. Now, numbering the C atoms in straight chain so that the substituents get the lowest position. So, numbering will be done from left to right. Two Br atoms are present at C2 position and one methyl group is present at C3 position. So, '2,2-dibromo-3-methyl' is added before root name. So, the complete name : 2,2-dibromo-3-methylpentane.
b) No. of C in longest straight chain = 6. hence, root name is 'hex' and ending name is 'ane' for alkane. Now, numbering the C atoms in straight chain so that the substituents get the lowest position. If we numbering from right to left the substituents get C3, C4 and C5 positions. But if we numbering from left to right the substituents get C2,C3 and C4 position. So, numbering is done from left to right. So methyl group is present at C2 position, Iodo group is present at C3 position and ethyl group is present at C4 position. So, '3-iodo-4-ethyl-2-methyl' is added before root name and we get the complete name.
c) No. of C in straight chain = 9. hence, root name is 'non' and ending name is 'ane' for alkane. now, numbering the C atom in straight chain so that the substituents get the minimum position. So, numbering is done from left to right. We see that methyl is present at C2 position and fluoro group is present at C4 position. So, '4-fluoro-2-methyl' is added before root name and we get the complete name: 4-fluoro-2-methylnonane.
