Chemistry: Atoms First (2nd Edition)

by Zumdahl, Steven S.; Zumdahl, Susan A.

Published by Cengage Learning

ISBN 10: 1305079248

ISBN 13: 978-1-30507-924-3

Chapter 21 - ChemWork Problems - Page 881k: 143

Answer

2-chloropropanoic acid

Work Step by Step

First, look at the product i.e. the ester. Now, the ester has two parts i.e. acid part and alcohol part. $CH_{3}-CH(Cl)-CO-$ is the acidic part present at the left side of the ester group. So, the acid is definitely $CH_{3}-CH(Cl)-CO-OH$. Complete reaction is written below:

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