Answer
See explanation
Work Step by Step
In alcohol, $-OH$ group is present. So, here O is bonded with H. That's why polarity of H is increased because of more electronegative 'O' so that it can make H-bond with the same molecule i.e. intermolecular H bond.
Similarly, for Carboxylic acid ($-COOH$) and amine ($-NH_{2}$), H is bonded with O and N respectively. So, they will also participate in intermolecular H bonding.
An example is illustrated below.
Alcohols, Carboxylic acids and amines groups can exhibit hydrogen bonding intermolecular forces.
$CH_{2}CF_{2}$ does not exhibit hydrogen bonding because: for H bonding to occur, 'H' must be attached to more electronegative atoms (N or O or F). Here in this molecule 'H" is attached to 'C' but not with 'F'. So, the 'H' is not that polarized to make intermolecular H bond with F.
Structure of $CH_{2}CF_{2}$ is as follows:
