Answer
B in BCl3 is trigonal planar, hence the hybridization is sp2 (3 bonds). On the other hand, B in BCl4- is tetragonal, hence hybridization is sp3 (4 bonds).
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Chemistry: Principles and Practice (3rd Edition)
by Reger, Daniel L.; Goode, Scott R.; Ball, David W.
Published by
Cengage Learning
ISBN 10:
0534420125
ISBN 13:
978-0-53442-012-3
Chapter 10 - Molecular Structure and Bonding Theories - Questions and Exercises - Questions - Page 416: 10.13
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