Answer
Both data set are of the same precision.
Work Step by Step
First, calculate the average of each set.
Set1:$(22.52+22.48+22.54)\div3=22.51$
Set2:$(22.64+22.58+22.62)\div3=22.61$
Next, calculate the absolute value of average deviations from each set.
Set1:$(|22.52-22.51|+|22.48-22.51|+|22.54-22.51|)\div3=0.02$
Set2:$(|22.64-22.61|+|22.58-22.61|+|22.62-22.61|)\div3=0.02$
Both sets have the same average deviation, therefore they both display the same precision.
