Answer
Limiting reagent is NaOH
Work Step by Step
We find the limiting reagent using the calculations below:
First
2 moles NaOH -- 1 mol CO$_2$
1,85 moles NaOH -- x
2x = 1,85 moles CO$_2$
x = 0,925 mol CO$_2$
Second
2 moles NaOH -- 1 mol CO$_2$
x -- 1 mol CO$_2$
x = 2 moles NaOH
We conclude that the limiting reactant is NaOH.
