Answer
0.244g KCl
Work Step by Step
Moles of AgNO3 in in 15 mL of 0.200 M solution
0.200 m/L * 0.015 L =0.003 mol AgNO3
0.003 mol AgNO3 * (74.55g KCl)/(1 mol) =0.244g KCl
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