Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 1 - Problems - Page 37: 1.43

Answer

(a) $314K$, $41^{\circ}C$ (b) $3683K$, $6170^{\circ}F$ (c) $10,520^{\circ}F$, $5827^{\circ}C$

Work Step by Step

Recall our conversion formulas: $^{\circ}C=(^{\circ}F-32) * \dfrac{5}{9}$ $^{\circ}F =( ^{\circ}C * \dfrac{9}{5})+32$ $K = {^{\circ}C}+273$ $^{\circ}C= K- 273$ $(a)$ $106^{\circ}F$ $^{\circ}C=(106^{\circ}F-32) * \dfrac{5}{9}$ $41^{\circ}C$ $K = {41^{\circ}C}+273$ $314K$ $(b)$ $3410^{\circ}C$ $K = {3410^{\circ}C}+273$ $3683K$ $^{\circ}F =( 3410^{\circ}C * \dfrac{9}{5})+32$ $6170^{\circ}F$ $(c)$ $6.1*10^3K$ $^{\circ}C= 6.1*10^3K- 273$ $5827^{\circ}C$ $^{\circ}F =( 5827^{\circ}C * \dfrac{9}{5})+32$ $10,520^{\circ}F$
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