Chemistry: The Science in Context (4th Edition)

Published by W.W. Norton & Co.
ISBN 10: 0393124177
ISBN 13: 978-0-39312-417-0

Chapter 1 - Matter and Energy: The Origin of the Universe - Problems - Page 37: 68

Answer

$1.10\text{ g/L}$

Work Step by Step

We will use the formula: $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$ First let's calculate the mass of the original air $\text{Mass}=1.00\times 10^6\text{ L}\times 1.20\text{ g/L}=1.20\times 10^6\text{ g}$ Then we determine the new density: $\text{Density}=\frac{1.20\times 10^6\text{ g}}{1.09\times 10^6\text{ L}}\approx 1.10\text{ g/L}$
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