General Chemistry 10th Edition

by Ebbing, Darrell; Gammon, Steven D.

Published by Cengage Learning

ISBN 10: 1-28505-137-8

ISBN 13: 978-1-28505-137-6

Chapter 16 - Acid-Base Equilibria - Questions and Problems - Page 703: 16.50

Answer

Please see the work below.

Work Step by Step

The chemical equation is $C_6H_5NH_2+H_2O\rightarrow \leftarrow C_6H_5NH_3^+ +OH^-$ The expression fro $K_b$ is $K_b=\frac{[C_6H_5NH_3]^+][OH^-]}{[C_6H_5NH_2]}$

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