General Chemistry 10th Edition

by Ebbing, Darrell; Gammon, Steven D.

Published by Cengage Learning

ISBN 10: 1-28505-137-8

ISBN 13: 978-1-28505-137-6

Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 934: 21.183

Answer

Please see the work below.

Work Step by Step

We can find the mass of $LiOH$ as $1.614\times 10^{-3} moc\space CO_2\times \frac{2 mol\space LiOH}{1 mol\space CO_2}\times\frac{23.95g\space LiOH}{1 mol\space LiOH}=7.731\times 10^{-2}g LiOH$

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