General Chemistry 10th Edition

by Ebbing, Darrell; Gammon, Steven D.

Published by Cengage Learning

ISBN 10: 1-28505-137-8

ISBN 13: 978-1-28505-137-6

Chapter 4 - Chemical Reactions - Questions and Problems - Page 177: 4.152

Answer

Please see the work below.

Work Step by Step

We know that $molarity=\frac{moles \space of\space solute }{Liters \space of \space solution}$ $molartiy=\frac{0.024502\space mol\space Na_2SO_4 }{0.0250L}=0.9801M$

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