General Chemistry 10th Edition

by Ebbing, Darrell; Gammon, Steven D.

Published by Cengage Learning

ISBN 10: 1-28505-137-8

ISBN 13: 978-1-28505-137-6

Chapter 6 - Thermochemistry - Questions and Problems - Page 262: 6.67

Answer

Please see the work below.

Work Step by Step

We know that $-369KJ\times \frac{1mol\space C_3H_8}{-2043KJ}\times \frac{44.06gC_3H_8}{1mol\space C_3H_8}=7.957gC_3H_8$

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