Answer
(a) $998.2g/L$
(b) $998.2kg/m^3$
(c) $9.982\times 10^{11} kg/km^{3}$
Work Step by Step
(a) To convert from g/cm3 to g/L, we need to multiply by 1000 (since there are 1000 cm3 in 1 L):
$Density\,of\, water\, at\, 20 °C in\,g/L = 0.9982 g/cm3 \times 1000 = 998.2 g/L.$
(b) To convert from g/cm3 to kg/m3, we need to divide by 1000 (since there are 1000 g in 1 kg) and then multiply by 1000 again (since there are 1000 cm3 in 1 m3):
$Density\,of\,water\, at\,20 °C\,in\, kg/m3 = 0.9982 g/cm3 / 1000 g/kg \times 1000 = 998.2 kg/m3.$
(c) To convert from kg/m3 to kg/km3, we need to divide by 1000^3 (since there are $1000 m$ in $1 km$):
$Density\,of\,water\,at\, 20 °C\,in\,kg/km^3 = 998.2 kg/m3=998.2/(1/10^9) =998.2\times 10^9=9.982\times 10^{11} kg/km^{3}.$
